Explanation of Mendel’s second law

Crossing a black short haired (BBSS) guinea pig with a brown long haired (bbss) guinea pig results in an F1 breed of black short haired (BbSs) guinea pigs. Inbreeding F1 black shorthair (BbSs) guinea pigs resulted in F2 progeny with 9 black shorthair, 3 black longhair, 3 brown longhair and 1 brown longhair guinea pig.

here,

The gene responsible for black color is B

Genotype BB is black

And the gene S responsible for short fur

Short hair genotype SS

Consequently, the black color and short hair genotype is BBSS

again,

Gene responsible for brown color b

Brown color genotype bb

And the gene responsible for long hair s

The long haired genotype ss

Consequently, the brown color and long hair genotype is bbss

The first progeny is F1 and the second progeny is F2

Parents : ♂ × ♀

Phenotype : Black color – short hair Brown color – long hair

Genotype : BBSS bbss

Gamete : (BS) (bs)

F1 Generation : BbSs

Self fertilization : F1×F1

Parents : ♂ × ♀

Phenotype : Black color Short hair     Black color Short hair

Genotype :        BbSs                             BbSs

Gamit : (BS) (Bs) (bS) (bs) (BS) (Bs) (bS) (bs)

F2 Generation (checker board)

Remarks: From the checker board, out of 16 guinea pigs, 9 are black-short hair, 3 black-long hair, 3 brown-long hair and 1 brown-long hair guinea pig.

Phenotypic Ratio: Black-Short Hair: Black-Long Hair: Brown-Long Hair: Brown-Long Hair = 9:3:3:1

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