Explanation of polygenic inheritance

A marriage of a Negro male (AABB) to a white (aabb) female results in mulatto offspring in the F1 lineage. Intermarriage between mulatto (AaBb) offspring in the F1 lineage resulted in F2 offspring with 1 Negro, 4 Dark, 6 Medium, 4 Light, and 1 White.

here,

Genotype of Negro male is AABB

The genotype of the white female is aabb

First progeny is F1 and second progeny is F2

 

Parents :             ♂        ×      ♀

Phenotype: Negro male     white female

Genotype :     AABB             aabb

Gamit :            (AB)              (ab)

F1 breed :                AaBb (mulatto)

 

Self fertilization : F1×F1

Parents :         ♂      ×       ♀

Phenotype: mulatto     mulatto

Genotype :    AaBb      AaBb

Gamit : (AB)(Ab)(aB)(ab)   (AB)(Ab)(aB)(ab).

F2 progeny (checker board)

Remarks : From the checker board, out of 16 children, 1 is Negro, 4 are dark, 6 are medium, 4 are light and 1 is white. In this case, the skin color has become darker as the number of expressed genes increases.

Phenotypic Ratio : Negro : Dark : Medium : Light : White = 1:4:6:4:1

 

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